JEE Main & Advanced JEE Main Solved Paper-2015

  • question_answer
    3g of activated charcoal was added to 50mL acetic solution (0.06N) in a flask. After an hour it was filtered and the strength of the filtrate was found to be 0.042 N. The amount of acetic acid adsorbed (per gram charcoal) is : [JEE Main Solved Paper-2015 ]

    A) 42 mg                   

    B) 54 mg

    C) 18 mg   

    D) 36 mg

    Correct Answer: C

    Solution :

    No. of meq. of                                                                                                 given                                                                                          No. of meq. of                                                                                                remaining                                                                                          ? 0.06 ?50 m eq. meq of                                                                                                 absorbed                                                                                                                                                                                                                                                                                                                                          of charcoal                                                                                                                                                                                                          adsorbed by 1 g of charcoal x\[=\frac{54}{3}=18g\]


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