JEE Main & Advanced JEE Main Solved Paper-2015

  • question_answer
    The molecular formula of a commercial resin used for exchanging ions in water softening is \[{{C}_{8}}{{H}_{7}}S{{O}_{3}}Na\]  (Mol. wt. 206). \[C{{a}^{2+}}\] ions by the resin when expressed in mole per gram resin ? [JEE Main Solved Paper-2015 ]

    A) \[\frac{2}{309}\]

    B) \[\frac{1}{412}\]

    C) \[\frac{1}{103}\]

    D) \[\frac{1}{206}\]

    Correct Answer: B

    Solution :

    \[\underset{\begin{smallmatrix}  (206g) \\  2mol \end{smallmatrix}}{\mathop{2{{C}_{8}}{{H}_{7}}S{{O}_{3}}}}\,Na+\underset{1mol}{\mathop{C{{a}^{2+}}}}\,\xrightarrow[{}]{{}}\] \[1molC{{a}^{2+}}\]        \[-2mol\,re\sin \] \[-412\,g\,re\sin \] Maximum \[C{{a}^{2+}}\] uptake\[=\frac{1mol}{412}/g\] of resin.


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