A) \[\frac{833}{4}\]
B) \[833\]
C) \[437\]
D) \[\frac{437}{4}\]
Correct Answer: B
Solution :
Variance \[=\frac{\sum\limits_{{}}^{{}}{x_{i}^{2}}}{n}-{{\left( \overline{x} \right)}^{2}}\] \[\Rightarrow \]\[{{\sigma }^{2}}=\left( \frac{{{2}^{2}}+{{4}^{2}}+{{6}^{2}}+...+{{100}^{2}}}{50} \right)-{{\left( \frac{2+4+...+100}{50} \right)}^{2}}\] \[\Rightarrow \]\[{{\sigma }^{2}}=3434-2601\] \[=833\]
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