A) \[5,1,1,+\frac{1}{2}\]
B) \[5,0,1,+\frac{1}{2}\]
C) \[5,0,0,+\frac{1}{2}\]
D) \[5,1,0,+\frac{1}{2}\]
Correct Answer: C
Solution :
\[E.C.=1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}4{{s}^{2}}3{{d}^{10}}4{{p}^{6}}5{{s}^{1}}\] Valence electron is present in 5s − subshell \[n=5.\ell =0,m=0,s=\frac{1}{2}\]
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