JEE Main & Advanced JEE Main Solved Paper-2014

  • question_answer
    For the non-stoichiometrereaction \[2A+B\to C+D,\]the following kinetic data were obtained inthree separate experiments, all at 298 K.
    Initial concentration (A) Initial Concentration (B) Initial rate of formation of C \[(mol\,{{L}^{-}}{{S}^{-}})\]
    \[0.1M\] \[0.1M\] \[1.2\times {{10}^{-3}}\]
    \[0.1M\] \[0.2M\] \[1.2\times {{10}^{-3}}\]
    \[0.2M\] \[0.1M\] \[2.4\times {{10}^{-3}}\]
    The rate law for the formation of C is : JEE Main  Solved  Paper-2014

    A) \[\frac{dc}{dt}=k[A]{{[B]}^{2}}\]              

    B) \[\frac{dc}{dt}=k[A]\]

    C) \[\frac{dc}{dt}=k[A][B]\]             

    D) \[\frac{dc}{dt}=k{{[A]}^{2}}[B]\]

    Correct Answer: B

    Solution :

    \[r=k{{[A]}^{x}}{{[B]}^{y}}\] \[1.2\times {{10}^{-3}}=k{{(0.1)}^{x}}{{[0.1]}^{y}}\]         ??.. (I) \[1.2\times {{10}^{-3}}=k{{(0.1)}^{x}}{{[0.2]}^{y}}\]         ??.. (II) From (I) and (II)\[\left( \frac{1}{2} \right)={{\left( \frac{1}{2} \right)}^{x}}\Rightarrow x=1\]??.. (III) Hence\[\frac{dc}{dt}=k(A)'\]


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