A) \[Z=1-\frac{Pb}{RT}\]
B) \[Z=1+\frac{Pb}{RT}\]
C) \[Z=1+\frac{RT}{Pb}\]
D) \[Z=1-\frac{a}{VRT}\]
Correct Answer: D
Solution :
\[\left( p+\frac{a}{{{v}^{2}}} \right)\left( v-b \right)=RT\] \[\Rightarrow \]\[\left( p+\frac{a}{{{v}^{2}}} \right)\left( v \right)=RT\Rightarrow pv+\frac{a}{v}=RT\] \[\Rightarrow \]\[\frac{pv}{RT}+\frac{a}{RTv}=1\]\[\Rightarrow \]\[z=1-\frac{a}{RTv}\]
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