question_answer

In the given circuit diagram, a wire is joining points B and D. The current in this wire is:

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A) 0.4 A   

B) 4 A

C) 2 A      

D) zero

Correct Answer: C

Solution :

[c] \[I=\frac{E}{{{R}_{eq}}}=\frac{E}{2},\operatorname{Re}q=2\Omega \] \[I=10A\] \[{{I}_{1}}=\frac{4}{5}I,\,\,{{I}_{2}}=\frac{1}{5}I\] \[{{I}_{1}}=8A,\,\,{{I}_{2}}=2A\] \[I_{1}^{'}=\frac{3}{5}\times 10=6A\] \[I_{2}^{'}=4A\] \[\Rightarrow {{I}_{BC}}=86=2A\]