JEE Main & Advanced JEE Main Paper Phase-I (Held on 09-1-2020 Morning)

  • question_answer
    A quantity f is given by \[f=\sqrt{\frac{h{{c}^{5}}}{G}}\] where c is speed of light, G universal gravitational constant and h is the Planck's constant. Dimension of f is that of                            [JEE MAIN Held on 09-01-2020 Morning]

    A) Energy

    B) Area

    C) Volume

    D) Momentum

    Correct Answer: A

    Solution :

    [a] \[\frac{hc}{\lambda }=E\Rightarrow \left[ hc \right]=\left[ M{{L}^{2}}{{T}^{-2}} \right]\left[ L \right]=\left[ M{{L}^{3}}{{T}^{-2}} \right]\] \[[c]=[L{{T}^{-1}}]\] \[[G]=[{{M}^{-1}}{{L}^{3}}{{T}^{-2}}]\]    \[\Rightarrow \,\,\,\,\left[ \sqrt{\frac{h{{c}^{5}}}{G}} \right]=\left[ M{{L}^{2}}{{T}^{-2}} \right]=\]Energy


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