| The correct order of the spin-only magnetic moments of the following complexes is: |
| (I) \[[Cr{{({{H}_{2}}O)}_{6}}]B{{r}_{2}}\] |
| (II) \[N{{a}_{4}}[Fe\,{{(CN)}_{6}}]\] |
| (III) \[N{{a}_{3}}[Fe{{({{C}_{2}}{{O}_{4}})}_{3}}]\,\,({{\Delta }_{0}}>P)\] |
| (IV) \[{{(E{{t}_{4}}N)}_{2}}[CoC{{l}_{4}}]\] |
| [JEE MAIN Held on 09-01-2020 Evening] |
A) \[(I)>(IV)>(III)>(II)\]
B) \[(III)>(I)>(IV)>(II)\]
C) \[(II)\approx (I)>(IV)>(III)\]
D) \[(III)>(I)>(II)>(IV)\]
Correct Answer: A
Solution :
\[N{{a}_{4}}[Fe{{(CN)}_{6}}]\to diamagnetic\,\,\,(\mu =0)\] \[[Cr{{({{H}_{2}}O)}_{6}}]B{{r}_{2}}\to Paramagnetic\,\,(\mu =\sqrt{24}\,BM)\] \[{{(NE{{t}_{4}})}_{2}}[CoC{{l}_{4}}]\to Paramagnetic\,\,(\mu =\sqrt{15}\,BM)\] \[N{{a}_{3}}[Fe{{({{C}_{2}}{{O}_{4}})}_{3}}]\to Paramagnetic\,\,(\mu =\sqrt{3}\,BM)\]
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