JEE Main & Advanced JEE Main Paper Phase-I (Held on 09-1-2020 Evening)

  • question_answer
    5 g of zinc is treated separately with an excess of
    (a) Dilute hydrochloric acid and
    (b) Aqueous sodium hydroxide.
    The ratio of the volumes of  \[{{H}_{2}}\]evolved in these two reactions is
    [JEE MAIN Held on 09-01-2020 Evening]

    A) \[1:4\]   

    B) \[2:1\]

    C) \[1:2\]

    D) \[1:1\]

    Correct Answer: D

    Solution :

    from one mole of \[Zn,\] \[1\text{ }mol\]of \[{{H}_{2}}\] is produced by both \[NaOH\]and\[HCl\]. \[\therefore \]  Molar ratio = Volume ratio i.e. \[1:1\]


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