A) Glucose reacts with hydroxylamine to form Oxime
B) The pentaacetate of glucose does not react With hydroxylamine to give oxime
C) Glucose exists in two crystalline forms \[\alpha \] and \[\beta \]
D) Glucose gives Schiff's test for aldehyde
Correct Answer: D
Solution :
[d] Glucose exists is two anomeric forms \[\alpha \] and\[\beta \]. It forms oxime with \[N{{H}_{2}}OH\]and its pentaacetate does not react with \[N{{H}_{2}}OH\] because its anomeric OH group is converted into acetate group. But glucose does not give Schiff test for aldehyde
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