A) - 6RT
B) + 6RT
C) + 6(2.303) RT
D) - 6(2.303) RT
Correct Answer: D
Solution :
[d] The rate constant of a reaction is given by \[k=A{{e}^{-{{E}_{a}}/RT}}\] The rate constant in presence of catalyst is Given by \[k'=A{{e}^{-E{{'}_{a}}/RT}}\] \[\frac{k'}{k}={{e}^{-(E{{'}_{a}}-{{E}_{a}}/RT}}\] \[{{10}^{6}}={{e}^{-(E{{'}_{a}}-{{E}_{a}})/RT}}\] ln \[{{10}^{6}}=-\frac{(E{{'}_{a}}-{{E}_{a}})}{RT}\] \[E{{'}_{a}}-{{E}_{a}}=-6(2.303)RT\]
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