A) 0.01
B) 0.20
C) 0.02
D) 0.10
Correct Answer: D
Solution :
Given \[P\left( A\cap \overline{B} \right)+P\left( \overline{A}\cap B \right)=\frac{2}{5}\] \[\Rightarrow \,\,\,\,\,\,\,P\left( A \right)+P\left( B \right)-2P\left( A\cap B \right)=\frac{2}{5}\] \[\Rightarrow \,\,\,\,\,P\left( A\cup B \right)-P\left( A\cap B \right)=\frac{2}{5}\] \[\Rightarrow \,\,\,\,\,\,\frac{1}{2}-\frac{2}{5}=P\left( A\cap B \right)\] \[\Rightarrow \,\,\,\,\,\,P\left( A\cap B \right)=\frac{1}{10}\]You need to login to perform this action.
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