A) 3.98
B) 4.02
C) 3.99
D) 4.01
Correct Answer: C
Solution :
\[\sum{{{x}_{i}}=200}\] and \[\sum{x_{_{i}}^{2}=2080}\] Now Actual Mean \[=\frac{200+11-9}{20}=\frac{202}{20}\] \[\therefore \] Actual variance \[=\frac{2080-81+121}{20}={{\left( \frac{202}{20} \right)}^{2}}\] \[106-{{\left( 10.1 \right)}^{2}}=106-102.01=3.99\]
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