JEE Main & Advanced JEE Main Paper Phase-I (Held on 08-1-2020 Evening)

  • question_answer
    \[\underset{x\to 0}{\mathop{lim}}\,\frac{\int\limits_{0}^{x}{t\sin (10t)dt}}{x}\]is equal to   [JEE MAIN Held on 08-01-2020 Evening]

    A) \[0\]

    B) \[\frac{1}{10}\]

    C) \[-\frac{1}{5}\]             

    D) \[-\frac{1}{10}\]

    Correct Answer: A

    Solution :

    \[\underset{x\to 0}{\mathop{lim}}\,\frac{\int\limits_{0}^{x}{t\sin (10t)dt}}{x}\] By L? hospital rule \[\underset{x\to 0}{\mathop{lim}}\,\frac{x\sin (10x)}{1}=0\]


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