A) \[\frac{1}{2}(6!)\]
B) \[\frac{5}{2}(6!)\]
C) \[{{5}^{6}}\]
D) 6!
Correct Answer: B
Solution :
[b] Exactly 1 digit will repeat which can be selected in \[^{5}{{C}_{1}}\] ways \[\therefore \] Total number of ways \[={{\,}^{5}}{{C}_{1}}.\frac{6!}{2!}=\frac{5}{2}(6!)\]
You need to login to perform this action.
You will be redirected in
3 sec
