question_answer

            Let P be a plane through the points (2, 1, 0), (4, 1, 1) and (5, 0, 1) and R be any point (2, 1, 6). Then the image of R in the plane P is                                                                                   [JEE MAIN Held on 07-01-2020 Morning]

A) (6, 5, 2) 

B) (4, 3, 2)

C) (3, 4, -2)        

D) (6, 5, -2)

Correct Answer: D

Solution :

[d] Plane is \[z+y-2z=3\] Image of (2, 1, 6) is given by Thus, \[\frac{{{x}_{1}}-2}{1}=\frac{{{y}_{1}}-1}{1}=\frac{{{z}_{1}}-6}{-2}=\frac{-2(2+1-12-3)}{6}=4\] \[\therefore \]      image of R = (6, 5, -2) Point is (6, 5, -2)