A) \[CC{{l}_{4}}<C{{H}_{4}}<CHC{{l}_{3}}\]
B) \[CHC{{l}_{3}}<C{{H}_{4}}=CC{{l}_{4}}\]
C) \[C{{H}_{4}}=CC{{l}_{4}}<CHC{{l}_{3}}\]
D) \[C{{H}_{4}}<CC{{l}_{4}}<CHC{{l}_{3}}\]
Correct Answer: C
Solution :
[c] \[CHC{{l}_{3}}\] is polar while \[C{{H}_{4}}\] and \[CC{{l}_{4}}\] are nonpolar. So, dipole moment order is: \[CHC{{l}_{3}}>C{{H}_{4}}=CC{{l}_{4}}\]
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