question_answer

The increasing order of \[p{{K}_{b}}\] for the following compounds will be    [JEE MAIN Held on 07-01-2020 Morning]

A) (B) < (C) < (A)

B) (B) < (A) < (C)

C) (C) < (A) < (B)

D) (A) < (B) < (C)

Correct Answer: B

Solution :

[b] \[p{{K}_{b}}=-\log {{K}_{b}}\] So, as \[{{K}_{b}}\] increases, \[p{{K}_{b}}\] decreases \[{{K}_{b}}:(B)>(A)>(C)\] \[p{{K}_{b}}:(B)<(A)<(C)\]