A) 2 mm
B) 33 mm
C) 22 mm
D) 12 mm
Correct Answer: C
Solution :
[c] \[m\simeq \frac{L}{{{f}_{0}}}\left( 1+\frac{D}{{{f}_{e}}} \right)\] \[\Rightarrow 375=\frac{150}{5}\left( 1+\frac{250}{{{f}_{e}}} \right)\] \[\Rightarrow 12.5=1+\frac{250}{{{f}_{e}}}\] \[\Rightarrow {{f}_{e}}=\frac{250}{11.5}=21.7\] \[\Rightarrow \]
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