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JEE Main & Advanced JEE Main Paper (Held On 9 April 2017)

  • question_answer
    A physical quantity P is described by the relation\[P={{a}^{1/2}}\,{{b}^{2}}{{c}^{3}}{{d}^{-4}}\]. If the relative errors in the measurement of \[a,\,b,\,c\] and d respectively, are 2%, 1%, 3% and 5%, then the relative error in P will be - [JEE Online 09-04-2017]

    A)  12%                                      

    B)  8%

    C)  25%                                      

    D)  32%

    Correct Answer: D

    Solution :

                      \[\frac{\Delta P}{P}=\frac{1}{2}\,\frac{\Delta a}{a}\,+2\,\frac{\Delta b}{b}\,+3\,\frac{\Delta c}{c}\,+4\,\frac{\Delta d}{d}\]                 \[=\frac{1}{2}\,\times 2+2\times 1+3\times 3+4\times 5\]                 \[=32%\]


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