JEE Main & Advanced JEE Main Paper (Held On 9 April 2017)

  • question_answer
    If \[\int\limits_{1}^{2}{\frac{dx}{{{({{x}^{2}}-2x+4)}^{\frac{3}{4}}}}\,=\frac{k}{k+5},}\] then k is equal to [JEE Online 09-04-2017]

    A)  4                                            

    B)  2

    C)  3                                            

    D)  1

    Correct Answer: D

    Solution :

                                                    \[\int_{1}^{2}{\frac{dx}{(x-1)\,+3{{)}^{3/2}}}}\] \[x-1=\sqrt{3}\,\tan Q\] \[=\sqrt{3}\,{{\sec }^{2}}Q\] \[\int_{0}^{\pi /6}{\frac{\sqrt{3}\,\sec \,dQ}{3\sqrt{3}\,\sec .\,3Q}}\] \[=\frac{1}{3}\,\int_{0}^{\pi /6}{\cos ec\,Q\,=\frac{1}{3}\,(\tan Q)_{0}^{\pi /6}}\] \[=\frac{1}{6}\,=\frac{k}{k+5}\,=k+5=6k\] \[=\]


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