JEE Main & Advanced JEE Main Paper (Held On 9 April 2017)

  • question_answer
    If three positive numbers a, b and c are in A.P. such that \[abc=8,\] then the minimum possible value of b is :   [JEE Online 09-04-2017]

    A)  \[{{4}^{\frac{2}{3}}}\]                                   

    B)  2

    C)  \[{{4}^{\frac{1}{3}}}\]                                   

    D)  4

    Correct Answer: B

    Solution :

                                    \[a+c=2b\] \[a.c.\left( \frac{a+c}{2} \right)=8\]


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