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JEE Main & Advanced JEE Main Paper (Held On 9 April 2016)

  • question_answer
    The ratio of work done by an ideal monatomic gas to the heat supplied to it in an isobaric process is :   JEE Main Online Paper (Held On 09 April 2016)

    A) \[\frac{3}{2}\]   

    B) \[\frac{2}{3}\]

    C) \[\frac{3}{5}\]                                   

    D) \[\frac{2}{5}\]

    Correct Answer: D

    Solution :

                    \[\Delta w=P\Delta V=nR\Delta T\]                 \[\Delta Q=n{{c}_{p}}\Delta T=\frac{5}{2}nR\Delta T\]                 \[\frac{\Delta Q}{\Delta Q}=\frac{2}{5}\]              


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