| \[{{O}_{3}}(g)+C{{l}^{\bullet }}(g)\to {{O}_{2}}(g)+Cl{{O}^{\bullet }}(g)\]……(i) |
| \[{{k}_{i}}=5.2\times {{10}^{9}}L\,mo{{l}^{-1}}{{s}^{-1}}\] |
| \[Cl{{O}^{\bullet }}(g)+{{O}^{\bullet }}(g)\to {{O}_{2}}(g)+C{{l}^{\bullet }}(g)\]……(ii) |
| \[{{k}_{ii}}=2.6\times {{10}^{10}}L\,mo{{l}^{-1}}{{s}^{-1}}\] |
A) \[1.4\times {{10}^{20}}L\,mo{{l}^{-1}}\,{{s}^{-1}}\]
B) \[5.2\times {{10}^{9}}L\,mo{{l}^{-1}}\,{{s}^{-1}}\]
C) \[3.1\times {{10}^{10}}L\,mo{{l}^{-1}}\,{{s}^{-1}}\]
D) \[2.6\times {{10}^{10}}L\,mo{{l}^{-1}}\,{{s}^{-1}}\]
Correct Answer: A
Solution :
On addition of eq.(1) & (2), we get \[{{O}_{3(g)}}+O_{(g)}^{\bullet }\xrightarrow[{}]{{}}2{{O}_{2(g)}}\] \[\therefore \]\[{{K}_{overall}}={{K}_{i}}\times {{K}_{ii}}\] \[=5.2\times {{10}^{9}}\times 2.6\times {{10}^{10}}\] \[=1.352\times {{10}^{20}}\] \[\simeq 1.4\times {{10}^{20}}\,L\,mo{{l}^{-1}}\,{{s}^{-1}}\]
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