JEE Main & Advanced JEE Main Paper (Held On 9 April 2016)

  • question_answer
    Figure shows elliptical path abcd of a planet around the sun S such that the area of triangle csa is\[\frac{1}{4}\]the area of the ellipse . (See figure) With db as the semi major axis, and ca as the semi minor axis. If \[{{t}_{1}}\]is the time taken for planet to go over path abc and \[{{t}_{2}}\]for path taken over cda then :                   JEE Main Online Paper (Held On 09 April 2016)

    A)                 \[{{t}_{1}}=3{{t}_{2}}\]                                 

    B) \[{{t}_{1}}={{t}_{2}}\]                

    C) \[{{t}_{1}}=2{{t}_{2}}\]                                 

    D) \[{{t}_{1}}=4{{t}_{2}}\]

    Correct Answer: A

    Solution :

    Total area = A Area of sabc\[=\frac{3A}{4}\] Area of sadc \[=\frac{A}{4}\] \[=\frac{3A}{4{{t}_{1}}}=\frac{A}{4{{t}_{2}}}\Rightarrow {{t}_{1}}=3{{t}_{2}}\]                


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