JEE Main & Advanced JEE Main Paper (Held On 9 April 2016)

  • question_answer
    Two particles are performing simple harmonic motion in a straight line about the same equilibrium point. The amplitude and time period for both particles are same and equal to A and T, respectively. At time t = 0 one particle has displacement A while the other one has displacement \[\frac{-A}{2}\]and they are moving towards each other If they cross each at time t, then t is :   JEE Main Online Paper (Held On 09 April 2016)

    A) \[\frac{T}{4}\]                                                   

    B) \[\frac{5T}{6}\]                

    C) \[\frac{T}{3}\]                   

    D) \[\frac{T}{6}\]

    Correct Answer: D

    Solution :


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