JEE Main & Advanced JEE Main Paper (Held On 9 April 2014)

  • question_answer
    Equation of the plane which passes through the point of inter section of lines \[\frac{x-1}{3}=\frac{y-2}{1}=\frac{z-3}{2}\]and\[\frac{x-3}{1}=\frac{y-1}{2}=\frac{z-2}{3}\]and has the largest distance from the origin is:   [JEE Main Online Paper ( Held On 09 Apirl  2014  )

    A) \[7x\text{ }+\text{ }2y\text{ }+\text{ }4z\text{ }=\text{ }54~~\]            

    B) \[3x\text{ }+\text{ }4y\text{ }+\text{ }5z\text{ }=\text{ }49\]

    C) \[4x\text{ }+\text{ }3y\text{ }+\text{ }5z\text{ }=\text{ }50\]              

    D) \[5x\text{ }+\text{ }4y\text{ }+\text{ }3z\text{ }=\text{ }57\]

    Correct Answer: C

    Solution :

                    Given equation of lines are \[\frac{x-1}{3}=\frac{y-2}{1}=\frac{z-3}{2}\]                                         ?(1) and\[\frac{x-3}{1}=\frac{y-1}{2}=\frac{z-2}{3}\]                 ?(2) Any point on line (1) is \[P(3\lambda +1,\lambda +2,2\lambda +3)\]and on line (2) is\[Q(\mu +3,2\mu +1,3\mu +2).\]On solving \[3\lambda +1=\mu +3\] and\[\lambda +2=2\mu +1\]we get \[\lambda =1,\mu =1\] \[\therefore \]Point of intersection of two lines is R (4, 3, 5) So, equation of plane ^ to OR where O is (0, 0, 0) and passing through R is\[4x+3y+5z=50\]


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