A) 1+
B) 2 +
C) 3+
D) 4 +
Correct Answer: C
Solution :
According to Faraday?s first law of electrolysis\[W=\frac{E\times i\times t}{96500}\] Where E = equivalent weight \[=\frac{\text{mol}\text{. mass of metal(M)}}{\text{oxidation state of metal(x)}}\] Substituting the value in the formula \[W=\frac{M}{x}\times \frac{i\times t}{96500}\] or\[x=\frac{M}{W}\times \frac{i\times t}{96500}=\frac{10\times 2\times 60\times 60}{96500\times 0.250}=3\] \[\left[ \text{Given:no}\text{. of moles}=\frac{M}{W}=.250 \right]\] Hence oxidation state of metal is (+3)
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