A) \[{{10}^{23}}A{{m}^{2}}\]
B) \[{{10}^{20}}A{{m}^{2}}\]
C) \[{{10}^{16}}A{{m}^{2}}\]
D) \[{{10}^{10}}A{{m}^{2}}\]
Correct Answer: A
Solution :
Given,\[B=4\times {{10}^{-5}}T\] \[{{R}_{E}}=6.4\times {{10}^{6}}m\] Dipole moment of the earth M = ? \[B=\frac{{{\mu }_{0}}}{4\pi }\frac{M}{{{d}^{3}}}\] \[4\times {{10}^{-5}}=\frac{4\pi \times {{10}^{-7}}\times M}{4\pi \times {{\left( 6.4\times {{10}^{6}} \right)}^{3}}}\] \[\therefore \]\[M\cong {{10}^{23}}A{{m}^{2}}\]
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