JEE Main & Advanced JEE Main Paper (Held On 9 April 2014)

  • question_answer
    The equation of state for a gas is given by PV = nRT + aV, where n is the number of moles and a is a positive constant. The initial temperature and pressure of one mole of the gas contained in a cylinder are \[{{T}_{o}}\]and \[{{P}_{o}}\]respectively. The work done by the gas when its temperature doubles isobaric ally will be:   [JEE Main Online Paper ( Held On 09 Apirl  2014  )

    A) \[\frac{{{P}_{o}}{{T}_{o}}R}{{{P}_{o}}-\alpha }\]

    B) \[\frac{{{P}_{o}}{{T}_{o}}R}{{{P}_{o}}+\alpha }\]

    C) \[{{P}_{o}}{{T}_{o}}R\ln 2\]                        

    D) \[{{P}_{o}}{{T}_{o}}R\]

    Correct Answer:


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