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JEE Main & Advanced JEE Main Paper (Held On 9 April 2014)

  • question_answer
    A capillary tube is immersed vertically in water and the height of the water column is x. When this arrangement is taken into a mine of depth d, the height of the water column is y. If R is the radius of earth, the ratio\[\frac{x}{y}\]is:   [JEE Main Online Paper ( Held On 09 Apirl  2014  )

    A) \[\left( 1-\frac{d}{R} \right)\]                    

    B) \[\left( 1-\frac{2d}{R} \right)\]

    C) \[\left( \frac{R-d}{R+d} \right)\]                               

    D) \[\left( \frac{R+d}{R-d} \right)\]

    Correct Answer: A

    Solution :

    A cceleration due to gravity changes with the depth,\[g'=g\left( 1-\frac{d}{R} \right)\] Pressure, \[P=\rho gh\] Hence ratio, \[\frac{x}{y}\]is\[\left( 1-\frac{d}{R} \right)\]


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