A)
B)
C)
D)
Correct Answer: C
Solution :
a = -C \[\frac{VdV}{dx}=-C\] \[VdV=-CdX\] \[\frac{{{V}^{2}}}{2}=-Cx+k\] \[x=-\frac{{{V}^{2}}}{2C}+\frac{K}{C}\]
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