JEE Main & Advanced JEE Main Paper (Held on 7 May 2012)

  • question_answer
    \[\underset{x\to 0}{\mathop{\lim }}\,\left( \frac{x-\sin x}{x} \right)\sin \left( \frac{1}{x} \right)\]   JEE Main Online Paper (Held On 07 May 2012)

    A) equals 1              

    B)                        equals 0

    C)                        does not exist                  

    D)                        equals? 1

    Correct Answer: B

    Solution :

                    Consider \[\underset{x\to 0}{\mathop{\lim }}\,\left( \frac{x-\sin x}{x} \right)\sin \left( \frac{1}{x} \right)\] \[=\underset{x\to 0}{\mathop{\lim }}\,\left[ \frac{x\left( 1-\frac{\sin x}{x} \right)}{x} \right]\times =\underset{x\to 0}{\mathop{\lim }}\,\sin \left( \frac{1}{x} \right)\] \[=\underset{x\to 0}{\mathop{\lim }}\,\left[ 1-\frac{\sin x}{x} \right]\times \underset{x\to 0}{\mathop{\lim }}\,\sin \left( \frac{1}{x} \right)\] \[=\left[ 1-\underset{x\to }{\mathop{\lim }}\,\frac{\sin x}{x} \right]\times \underset{x\to 0}{\mathop{\lim }}\,\sin \left( \frac{1}{x} \right)\] \[=0\times \underset{x0}{\mathop{\lim }}\,\sin \left( \frac{1}{x} \right)=0\]


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