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JEE Main & Advanced JEE Main Paper (Held on 7 May 2012)

  • question_answer
    The range of the function \[f\left( x \right)=\frac{x}{1+|x|},x\in R,\]is   JEE Main Online Paper (Held On 07 May 2012)

    A) R                                            

    B)                        -1,1

    C)                        R- {0}                    

    D)                        [-1, 1]  

    Correct Answer: B

    Solution :

                    \[f(x)=\frac{x}{1+\left| x \right|},x\in R\] If\[x>0,|x|=x\Rightarrow f(x)=\frac{x}{1+x}\]which is not defined for \[x=-1\] Thus f(x) defined for all values of R except 1and- 1 Hence, range =(-1,1).


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