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JEE Main & Advanced JEE Main Paper (Held on 7 May 2012)

  • question_answer
    The entropy of a sample of a certain substance increases by \[0.836\,J\,{{K}^{-1}}\] on adding reversibly0.3344 J of heat at constant temperature. The temperature of the sample is:   JEE Main Online Paper (Held On 07 May 2012)

    A) 2.5K                                      

    B)                        0.3K

    C)                        0.016K                                  

    D)                        0.4K

    Correct Answer: D

    Solution :

                    \[\Delta S=\frac{\Delta H}{T};T=\frac{\Delta H}{\Delta S}=\frac{0.3344}{0.836}=0.4K\]


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