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JEE Main & Advanced JEE Main Paper (Held on 7 May 2012)

  • question_answer
    If the straight lines \[\text{x}+\text{3y}=\text{4},\text{3x}+\text{y}=\text{4}\]and \[\text{x}+\text{y}=0\]form a triangle, then the triangle is   JEE Main Online Paper (Held On 07 May 2012)

    A) scalene

    B)                        equilateral triangle        

    C)                        isosceles

    D)                        right angled isosceles

    Correct Answer: C

    Solution :

                    Let equation of \[AB:x+3y=4\] Let equation of\[BC:3x+y=4\] Let equation of \[CA:x+y=0\] Now, By solving these equations we get \[A=(-2,2),B=(1,1)\]and\[C=(2,-2)\] Now,\[AB=\sqrt{9+1}=\sqrt{10},\] \[BC=\sqrt{1+9}=\sqrt{10}\] and\[CA=\sqrt{16+16}=\sqrt{32}\] Since, length of AB and BC are same therefore triangle is isosceles.


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