JEE Main & Advanced JEE Main Paper (Held On 26 May 2012)

  • question_answer
    The resistance of a wire is R. It is bent at the middle by 180° and both the ends are twisted together to make a shorter wire. The resistance of the new wire is   JEE Main Online Paper (Held On 26-May-2012)  

    A) 2R                          

    B)                        R/2

    C)                        R/4                        

    D)                        R/S

    Correct Answer: C

    Solution :

                    Resistance of wire \[(R)=\rho \frac{l}{A}\] If wire is bent in the middle then\[l'=\frac{l}{2'}A'=2A\] \[\therefore \]New resistance, \[R'=\rho \frac{l'}{A'}\] \[=\frac{\rho \frac{l}{2}}{2A}=\frac{\rho l}{4A}=\frac{R}{4}.\]


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