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JEE Main & Advanced JEE Main Paper (Held On 26 May 2012)

  • question_answer
    One mole of\[{{O}_{2(g)}}\]and two moles of\[S{{O}_{2(g)}}\] were heated in a closed vessel of one-litre capacity at1098 K. At equilibrium 1.6 moles of\[S{{O}_{3(g)}}\] were found. The equilibrium constant \[{{K}_{c}}\] of the reaction would be.   JEE Main Online Paper (Held On 26-May-2012)  

    A) 30                                          

    B)                        40

    C)                        80    

    D)                        60

    Correct Answer: C

    Solution :

      \[{{O}_{2}}\]\[{{O}_{2}}+\] \[2S{{O}_{2}}\] \[2S{{O}_{3}}\]
    at t = 0 1 2 0
    At equil. \[(1-\alpha )\] \[2(1-\alpha )\] \[2\alpha \]
    Given at equilibrium \[2\alpha =1.6\] \[\alpha =0.8\] \[{{K}_{C}}=\frac{{{(2\alpha )}^{2}}}{(1-\alpha ){{(2-2\alpha )}^{2}}}=\frac{{{(0.8)}^{2}}}{(1-0.8){{(1-0.8)}^{2}}}\] \[=\frac{0.64}{0.002}\] \[{{K}_{C}}=80\]                                


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