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JEE Main & Advanced JEE Main Paper (Held On 26 May 2012)

  • question_answer
    The following sets of quantum numbers represent four electrons in an atom.   JEE Main Online Paper (Held On 26-May-2012)  
     (i) \[n=4,l=1\]
     (ii) \[n=4,l=0\]
     (iii)\[n=3,l=2\]
     (iv) \[n=3,l=1\]
    The sequence representing increasing order of energy, is

    A) (iii)<(i)<(iv)<(ii)                

    B) (iv)<(ii)<(iii)<(i)

    C) (i)<(iii)<(ii)<(iv)                

    D) (ii)<(iv)<(i)<(iii)

    Correct Answer: B

    Solution :

    (i) 4 p                        (ii) 4s (iii) 3 d    (iv) 3p According to Bohr Bury's \[(n+\ell )\] rule, increasing order of energy will be (iv)<(ii)<(iii)<(i). Note : If the two orbitals have same value of (n + i) then the orbital with lower value of n will be filled first.


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