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JEE Main & Advanced JEE Main Paper (Held On 25 April 2013)

  • question_answer
                    5-digit numbers are to be formed using 2,3,5,7,9 without repeating the digits. If p be the number of such numbers that exceed  20000 and \[q\] be the number of those that lie between 30000 and 90000 , then p:q is :     JEE Main Online Paper ( Held On 25  April 2013 )

    A)                 6:5                                         

    B)                                        3:2

    C)                                        4:3                                         

    D)                                        5:3

    Correct Answer: D

    Solution :

                   
    P: 0 0 0 0 0 Place
    5 4 3 2 1 ways
    Total no. of ways \[=5!=120\] Since all numbers are > 20,000             \[\therefore \]all numbers 2,3,5, 7,9 can come at first    place.                              
    q: 0 0 0 0 0 Place
    3 4 3 2 1 ways
    Total no. of ways \[=3\times 4!=72\] (\[\because \] 2 and 9 can not be put at first place)                 So,\[p:q=120:72=5:3\]        


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