A) \[\operatorname{Pd}Cl_{4}^{2-}\]
B) \[\operatorname{Fe}Cl_{4}^{2-}\]
C) \[{{C}_{O}}Cl_{4}^{2-}\]
D) \[NiCl_{4}^{2-}\]
Correct Answer: A
Solution :
\[{{[PdC{{l}_{4}}]}^{2-}}\] is \[ds{{p}^{2}}\]hybridized and square planar in shape.
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