JEE Main & Advanced JEE Main Paper (Held On 22 April 2013)

  • question_answer The wave number of the first emission line in the Balmer series of H-Spectrum is: (R= Rydberg constant):     JEE Main  Online Paper (Held On 22 April 2013)

    A)  \[\frac{5}{36}\operatorname{R}\]                  

    B)  \[\frac{9}{400}\operatorname{R}\]

    C)  \[\frac{7}{6}\operatorname{R}\]                                     

    D)   \[\frac{3}{4}\operatorname{R}\]

    Correct Answer: A

    Solution :

     \[\bar{v}=R{{Z}^{2}}\left( \frac{1}{{{2}^{2}}}-\frac{1}{{{3}^{2}}} \right)\] \[=R\left( \frac{1}{4}-\frac{1}{9} \right)=\frac{5R}{36}\]


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