JEE Main & Advanced JEE Main Paper (Held On 22 April 2013)

  • question_answer The density of 3M solution of sodium chloride is  1.252\[~\text{gm}{{\text{L}}^{-1}}\]. The molality of the solution will be: (molar mass,\[\text{NaCI }=\text{85}.\text{5 g mo}{{\text{l}}^{\text{-1}}}\])     JEE Main  Online Paper (Held On 22 April 2013)

    A)  2.60 m                  

    B)  2.18 m

    C)  2.79 m                  

    D)  3.00 m

    Correct Answer: C

    Solution :

     The relation between molarity (M) and molality(m)is \[d=M\left( \frac{1}{m}+\frac{{{M}_{2}}}{1000} \right),{{M}_{2}}=Mol.\]Mass of solute On putting value on solving \[m=2.79\]

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