JEE Main & Advanced JEE Main Paper (Held On 19 May 2012)

  • question_answer
    The pressure of an ideal gas varies with volume as \[P=\alpha V,\] where a is a constant. One mole of the gas is allowed to undergo expansion such that its volume becomes 'm times its initial volume. The work done by the gas in the process is     JEE Main  Online Paper (Held On 19  May  2012)

    A) \[\frac{\alpha V}{2}\left( {{m}^{2}}-1 \right)\]                   

    B)                        \[\frac{{{\alpha }^{2}}{{V}^{2}}}{2}\left( {{m}^{2}}-1 \right)\]

    C)                        \[\frac{\alpha }{2}\left( {{m}^{2}}-1 \right)\]                      

    D)                        \[\frac{\alpha {{V}^{2}}}{2}\left( {{m}^{2}}-1 \right)\]

    Correct Answer: D

    Solution :

                    Given \[P=\alpha V\] Work done, \[w=\int\limits_{V}^{mV}{PdV}\] \[=\int\limits_{V}^{mV}{\alpha V\,dV}=\frac{\alpha {{V}^{2}}}{2}({{m}^{2}}-1).\]


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