JEE Main & Advanced JEE Main Paper (Held On 19 May 2012)

  • question_answer
    Two point masses of mass \[{{m}_{1}}=fM\]and \[{{m}_{2}}=(1-f)M(f<1)\]are in outer space (far from gravitational influence of other objects) at a distance R from each other. They move in circular orbits about their centre of mass with angular velocities \[{{\omega }_{1}}\]) for\[{{m}_{1}}\]and \[{{\omega }_{2}}\]for\[{{m}_{2}}\]. In that case     JEE Main  Online Paper (Held On 19  May  2012)

    A) \[(1-f){{\omega }_{1}}=f\omega \]

    B)                        \[{{\omega }_{1}}={{\omega }_{2}}\]and independent of f

    C)                        \[f{{\omega }_{1}}=(1-f){{\omega }_{2}}\]

    D)                        \[{{\omega }_{1}}={{\omega }_{2}}\] and depend on f

    Correct Answer: B

    Solution :

                    Angular velocity is the angular displacement per unit time i.e., \[\omega =\frac{\Delta \theta }{\Delta t}\]                 Here \[{{w}_{1}}={{w}_{2}}\]and independent of f.


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