A) \[{{10}^{-1}}N/{{m}^{2}}\]
B) \[{{10}^{-2}}N/{{m}^{2}}\]
C) \[{{10}^{-3}}N/{{m}^{2}}\]
D) \[{{10}^{-4}}N/{{m}^{2}}\]
Correct Answer: B
Solution :
\[\eta ={{10}^{-2}}\] poise \[v=18km/h=\frac{18000}{3600}=5m/s\] \[l=5m\]Strain rate \[=\frac{v}{l}\] Coefficient of viscosity, \[\eta =\frac{\text{shearing}\,\text{stress}}{\text{strain}\,\text{rate}}\] \[\therefore \]shearing stress \[=\eta \times \]strain rate \[={{10}^{-2}}\times \frac{5}{5}={{10}^{-2}}N{{m}^{-2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
