What is the value of g at the place?
JEE Main Online Paper (Held On 19 April 2016)
A) \[9.81m/{{s}^{2}}\]
B) \[9.87m/{{s}^{2}}\]
C) \[9.91m/{{s}^{2}}\]
D) \[10.0m/{{s}^{2}}\]
Correct Answer: B
Solution :
From graph it is clear that when \[L=lm,{{T}^{2}}=4{{s}^{2}}\] As we know, \[T=2\pi \sqrt{\frac{L}{g}}\]\[\Rightarrow \]\[g=\frac{4{{\pi }^{2}}L}{{{T}^{2}}}\] \[=4\times {{\left( \frac{22}{7} \right)}^{2}}\times \frac{1}{4}={{\left( \frac{22}{7} \right)}^{2}}\] \[\therefore \]\[g=\frac{484}{48}=9.87\,m\text{/}{{s}^{2}}\]
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