A) Cr
B) V
C) Ti
D) Mn
Correct Answer: D
Solution :
\[\underset{(green)}{\mathop{Mn{{O}_{2}}+2KOH+KN{{O}_{3}}\to {{K}_{2}}Mn{{O}_{4}}+KN{{O}_{2}}+{{H}_{2}}O}}\,\] Disproportionation reaction is as following: \[\underset{(purple)}{\mathop{MnO_{4}^{-}2+4{{H}^{+}}\to 2MnO_{4}^{-}+Mn{{O}_{2}}+2{{H}_{2}}O}}\,\]
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