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JEE Main & Advanced JEE Main Paper (Held On 15 April 2018) Slot-I

  • question_answer
    A tuning fork vibrates with frequency \[256Hz\]and gives one best per second with the third normal mode of vibration of an open pipe. What is the length of the pipe? (Speed of sound of air is \[340m{{s}^{-1}}\]) [JEE Online 15-04-2018]

    A) \[190cm\]                    

    B) \[180cm\]                    

    C) \[220cm\]                    

    D) \[200cm\]

    Correct Answer: D

    Solution :

    Frequency of tuning fork \[=256Hz\] Frequency of open pipe \[=256\pm 1Hz\] Frequency of third normal mode of vibration of an open pipe is\[v=\frac{3v}{2l}\] here \[l\text{ }=\]length of pipe \[\frac{3\times 340}{2\times l}=255\] \[l=200cm\]


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